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0e7b06e9d0
golangci-lint reports these: The copy of the 'for' variable "kmsID" can be deleted (Go 1.22+) (copyloopvar) Signed-off-by: Niels de Vos <ndevos@ibm.com>
89 lines
2.0 KiB
Go
89 lines
2.0 KiB
Go
/*
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Copyright 2021 The Ceph-CSI Authors.
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Licensed under the Apache License, Version 2.0 (the "License");
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you may not use this file except in compliance with the License.
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You may obtain a copy of the License at
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http://www.apache.org/licenses/LICENSE-2.0
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Unless required by applicable law or agreed to in writing, software
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distributed under the License is distributed on an "AS IS" BASIS,
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WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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See the License for the specific language governing permissions and
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limitations under the License.
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*/
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package util
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import (
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"context"
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"errors"
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"testing"
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"time"
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)
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func TestExecCommandWithTimeout(t *testing.T) {
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t.Parallel()
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type args struct {
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ctx context.Context
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program string
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timeout time.Duration
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args []string
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}
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tests := []struct {
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name string
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args args
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stdout string
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expectedErr error
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wantErr bool
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}{
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{
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name: "echo hello",
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args: args{
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ctx: context.TODO(),
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program: "echo",
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timeout: time.Second,
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args: []string{"hello"},
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},
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stdout: "hello\n",
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expectedErr: nil,
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wantErr: false,
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},
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{
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name: "sleep with timeout",
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args: args{
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ctx: context.TODO(),
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program: "sleep",
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timeout: time.Second,
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args: []string{"3"},
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},
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stdout: "",
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expectedErr: context.DeadlineExceeded,
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wantErr: true,
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},
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}
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for _, tt := range tests {
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t.Run(tt.name, func(t *testing.T) {
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t.Parallel()
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stdout, _, err := ExecCommandWithTimeout(tt.args.ctx,
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tt.args.timeout,
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tt.args.program,
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tt.args.args...)
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if (err != nil) != tt.wantErr {
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t.Errorf("ExecCommandWithTimeout() error = %v, wantErr %v", err, tt.wantErr)
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return
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}
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if tt.wantErr && !errors.Is(err, tt.expectedErr) {
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t.Errorf("ExecCommandWithTimeout() error expected got = %v, want %v", err, tt.expectedErr)
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}
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if stdout != tt.stdout {
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t.Errorf("ExecCommandWithTimeout() got = %v, want %v", stdout, tt.stdout)
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}
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})
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}
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}
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