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22ff5c0911
snapClient.SnapshotV1alpha1Client and also update kube dependency Signed-off-by: Humble Chirammal <hchiramm@redhat.com>
95 lines
3.3 KiB
Go
95 lines
3.3 KiB
Go
/*
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Copyright 2014 The Kubernetes Authors.
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Licensed under the Apache License, Version 2.0 (the "License");
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you may not use this file except in compliance with the License.
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You may obtain a copy of the License at
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http://www.apache.org/licenses/LICENSE-2.0
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Unless required by applicable law or agreed to in writing, software
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distributed under the License is distributed on an "AS IS" BASIS,
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WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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See the License for the specific language governing permissions and
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limitations under the License.
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*/
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package serviceaccount
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import (
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"fmt"
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"strings"
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apimachineryvalidation "k8s.io/apimachinery/pkg/api/validation"
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)
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const (
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ServiceAccountUsernamePrefix = "system:serviceaccount:"
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ServiceAccountUsernameSeparator = ":"
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ServiceAccountGroupPrefix = "system:serviceaccounts:"
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AllServiceAccountsGroup = "system:serviceaccounts"
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)
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// MakeUsername generates a username from the given namespace and ServiceAccount name.
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// The resulting username can be passed to SplitUsername to extract the original namespace and ServiceAccount name.
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func MakeUsername(namespace, name string) string {
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return ServiceAccountUsernamePrefix + namespace + ServiceAccountUsernameSeparator + name
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}
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// MatchesUsername checks whether the provided username matches the namespace and name without
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// allocating. Use this when checking a service account namespace and name against a known string.
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func MatchesUsername(namespace, name string, username string) bool {
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if !strings.HasPrefix(username, ServiceAccountUsernamePrefix) {
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return false
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}
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username = username[len(ServiceAccountUsernamePrefix):]
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if !strings.HasPrefix(username, namespace) {
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return false
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}
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username = username[len(namespace):]
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if !strings.HasPrefix(username, ServiceAccountUsernameSeparator) {
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return false
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}
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username = username[len(ServiceAccountUsernameSeparator):]
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return username == name
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}
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var invalidUsernameErr = fmt.Errorf("Username must be in the form %s", MakeUsername("namespace", "name"))
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// SplitUsername returns the namespace and ServiceAccount name embedded in the given username,
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// or an error if the username is not a valid name produced by MakeUsername
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func SplitUsername(username string) (string, string, error) {
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if !strings.HasPrefix(username, ServiceAccountUsernamePrefix) {
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return "", "", invalidUsernameErr
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}
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trimmed := strings.TrimPrefix(username, ServiceAccountUsernamePrefix)
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parts := strings.Split(trimmed, ServiceAccountUsernameSeparator)
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if len(parts) != 2 {
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return "", "", invalidUsernameErr
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}
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namespace, name := parts[0], parts[1]
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if len(apimachineryvalidation.ValidateNamespaceName(namespace, false)) != 0 {
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return "", "", invalidUsernameErr
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}
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if len(apimachineryvalidation.ValidateServiceAccountName(name, false)) != 0 {
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return "", "", invalidUsernameErr
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}
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return namespace, name, nil
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}
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// MakeGroupNames generates service account group names for the given namespace
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func MakeGroupNames(namespace string) []string {
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return []string{
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AllServiceAccountsGroup,
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MakeNamespaceGroupName(namespace),
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}
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}
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// MakeNamespaceGroupName returns the name of the group all service accounts in the namespace are included in
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func MakeNamespaceGroupName(namespace string) string {
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return ServiceAccountGroupPrefix + namespace
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}
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